A pupil pushes a wheelbarrow carrying 30kg sand it accelerates from rest to 2m/s in the distance of 1m. If the friction is on the wheelbarrow is 0.5n find accelaration
average velocity ... (0 + 2) / 2 = 1 m/s
takes one second to travel 1 m and accelerate to 2 m/s
V^2 = Vo + 2a*d.
2^2 = 0 + 2a*1,
a = 2m/s^2.
To find the acceleration, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration. In this case, the net force is the force exerted by the pupil minus the force of friction.
1. Calculate the force exerted by the pupil:
The force exerted by the pupil can be calculated using the formula:
Force = mass x acceleration.
Given:
Mass (m) = 30 kg
Acceleration (a) = 2 m/s^2
Substituting the given values in the formula:
Force = 30 kg x 2 m/s^2 = 60 N
2. Calculate the force of friction:
The force of friction can be calculated using the formula:
Force of friction = coefficient of friction x normal force.
Given:
Coefficient of friction (μ) = 0.5 N
Normal force = mass x gravitational acceleration
Substituting the values in the formula:
Normal force = 30 kg x 9.8 m/s^2 = 294 N
Force of friction = 0.5 N x 294 N = 147 N
3. Calculate the net force:
Net force = Force exerted by the pupil - Force of friction
Net force = 60 N - 147 N = -87 N (negative sign indicates opposition to the motion)
4. Calculate the acceleration:
Using the formula from Newton's second law, we can rearrange it to solve for acceleration:
Net force = mass x acceleration
Substituting the values:
-87 N = 30 kg x acceleration
Solving for acceleration:
acceleration = -87 N / 30 kg ≈ -2.9 m/s^2
Therefore, the acceleration of the wheelbarrow is approximately -2.9 m/s^2.
To find the acceleration of the wheelbarrow, we can use Newton's second law of motion:
F_net = m * a
Where:
F_net is the net force acting on the wheelbarrow,
m is the mass of the wheelbarrow, and
a is the acceleration of the wheelbarrow.
In this case, we need to consider two forces acting on the wheelbarrow: the force applied by the pupil (pushing force) and the force of friction.
The pushing force applied by the pupil causes the acceleration, while the force of friction opposes the motion and acts in the opposite direction.
The net force can be calculated using the equation:
F_net = F_push - F_friction
Given:
Mass of the wheelbarrow (m) = 30 kg
Force of friction (F_friction) = 0.5 N
Using the information from the question, the distance traveled (s) is given as 1 m, and the final velocity (v) is given as 2 m/s. However, we do not need these values to calculate the acceleration.
First, we need to find the pushing force (F_push). To do that, we use the equation:
F_push = m * a
Rearranging the equation, we get:
a = F_push / m
Now, substitute the given values:
a = (F_push) / (30 kg)
Next, we need to consider the friction force. The force of friction can be calculated using the equation:
F_friction = μ * m * g
Where:
μ is the coefficient of friction, and
g is the acceleration due to gravity (approximately 9.8 m/s²).
However, the coefficient of friction is not given in the problem. Without the coefficient of friction, it is not possible to calculate the acceleration accurately.
To summarize, without the coefficient of friction, we cannot determine the exact acceleration of the wheelbarrow. Therefore, we need additional information or assume a specific value for the coefficient of friction to calculate the acceleration.