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If y^2=1+(2/x) find (d^2y)/dx^2 in terms of x and y

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asked by Anonymous
  1. y^2 = 1 + 2/x
    2y dy/dx = -2/x^2
    y' = -2/(2yx^2) = -1/(y x^2)
    using the quotient rule,
    y '' = (yx^2(0) - (-1)(x(2x) + x^2 dy/dx) )/(y^2 x^4)
    = (2xy + x^2(-1/(yx^2) )/(y^2x^4)
    = (2xy - 1/y)/(y^2 x^4)
    = (2x y^2 - 1)/(y^3 x^4)

    check my algebra

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    posted by Reiny

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