On heating 25g of a saturated solution to dryness at 60oc, 4g of anhydrous salt was recovered. Calculate its solubility in grams per 100g of solvent
of the 25g, 21 g was solvent. The solubility was 4g/21gsolvent which is the same as 19g/100g solvent
Oo this website is so interested
To calculate the solubility of the salt in grams per 100 grams of solvent, we need to use the given information.
The mass of the anhydrous salt recovered is 4g. This means that 4g of the salt was present in the 25g of the saturated solution that was heated to dryness.
To calculate the solubility, we need to find the total mass of the saturated solution. This is the sum of the mass of the anhydrous salt and the mass of the remaining water in the solution.
The mass of the anhydrous salt is 4g. We need to subtract this from the total mass:
Total mass of solution = mass of anhydrous salt + mass of water
Total mass of solution = 4g + mass of water
Since the total mass of the solution is 25g, we can rewrite the equation as:
25g = 4g + mass of water
To find the mass of water, we subtract 4g from both sides:
25g - 4g = 4g + mass of water - 4g
21g = mass of water
Now that we know the mass of water, we can calculate the solubility by dividing the mass of anhydrous salt by the mass of solvent (water) and multiplying by 100:
Solubility (in grams per 100g of solvent) = (mass of anhydrous salt / mass of water) x 100
Substituting the values we found:
Solubility = (4g / 21g) x 100
Calculating this, we get:
Solubility = 19.05 grams per 100 grams of solvent
Therefore, the solubility of the salt is 19.05 grams per 100 grams of solvent.