the volume of water drum is halved every 2 days of a drought. If the volume of water in the drum was initially 1,000,000 gallon, what was the approximate volume after 10 days.
I'll help you with this problem after you answer my questions about your last problem.
2^5 = 32
or, if that's too opaque, (1/2)^(10/2) = 1/32
To find the approximate volume of water in the drum after 10 days, we need to determine how many times the volume is halved in that period.
First, let's calculate how many times the volume is halved every 2 days. We divide the number of days by the interval at which the volume is halved:
10 days / 2 days = 5 times
This means the volume is halved 5 times during the 10-day period.
Since the volume is halved each time, we can calculate the final volume by dividing the initial volume by 2 raised to the power of the number of halvings:
Final volume = Initial volume / (2^Number of halvings)
In this case, the initial volume is 1,000,000 gallons and the number of halvings is 5:
Final volume = 1,000,000 gallons / (2^5)
Final volume = 1,000,000 gallons / 32
Final volume ≈ 31,250 gallons
Therefore, the approximate volume of water in the drum after 10 days of drought will be approximately 31,250 gallons.