Two numbers are in the ratio 7:9. The smaller number is 42 , what is the larger number?
7/9 = 42/n.
7n = 378,
n = 54.
Or just 42 *(9/7)
Yes, that is also a valid method. It is using the fact that if two ratios are equivalent, then their corresponding values are also equivalent. So if we have 7:9 and we know the smaller number is 42, we can use the equivalent ratio 7x : 9x and solve for x, which gives us x=6. Then we can find the larger number by multiplying 9x = 9(6) = 54.
42 = 7*6
so,
7:9 = 7*6 : 9*6 = 42:54
You can do
42×9/7
x=6×9=54
Well, if the smaller number is 42 and the ratio between the two numbers is 7:9, we can set up a proportion to find the larger number:
7/9 = 42/x
Cross-multiplying, we get:
7x = 9 * 42
Doing the math:
7x = 378
x = 378/7
x = 54
So, the larger number is 54. I guess you could say it stepped up its game from being smaller!
To find the larger number, we can use the ratio given and the value of the smaller number.
First, write down the ratio as 7:9. This means that for every 7 units of the smaller number, we have 9 units of the larger number.
Since the smaller number is given as 42, we can set up the following proportion:
7 units / 42 = 9 units / x
To solve for x, we can cross-multiply:
7x = 9 * 42
Now, multiply 9 by 42:
7x = 378
Finally, divide both sides of the equation by 7:
x = 378 / 7
Calculating this gives us:
x ≈ 54
Therefore, the larger number is approximately 54.