What happens when BaCl2.2H2O reacts with KCl
There is no reaction between the two as solids or when either or both are in solution.
When BaCl2·2H2O (barium chloride dihydrate) reacts with KCl (potassium chloride), a double displacement (or precipitation) reaction occurs, resulting in the formation of BaCl2 (barium chloride) and K2SO4 (potassium sulfate).
To understand why this reaction occurs, we need to consider the solubility rules of different compounds. BaCl2 is soluble in water, and KCl is also soluble in water. However, BaSO4 (barium sulfate), one of the products of this reaction, is insoluble in water and forms a solid precipitate. On the other hand, KCl remains soluble in water.
The balanced chemical equation for the reaction is as follows:
BaCl2·2H2O + 2KCl → BaCl2 + K2SO4·2H2O
To determine the products of this reaction, you need to know the chemical formulas of the reactants (BaCl2·2H2O and KCl), along with their solubility properties. Additionally, understanding the concept of double displacement reactions and having knowledge of common solubility rules with respect to ionic compounds is essential.