Oxidation no of I3 raised to minus charge ion??
https://www.quora.com/What-is-the-oxidation-state-of-the-three-Iodine-atoms-in-KI_3
The answer is the oxidation number of two of them is zero, the third, -1
To determine the oxidation number of I3- (triiodide ion), we need to consider two things:
1. The overall charge of the ion: The triiodide ion (I3-) has a charge of -1.
2. The oxidation numbers of each element: The oxidation number of iodine (I) is typically -1 in compounds, except when combined with more electronegative elements (such as oxygen or fluorine).
With these points in mind, we can set up an equation to determine the oxidation number of iodine in I3-. Let's assign the oxidation number of iodine as x:
3(I) + x = -1
Since there are three iodine atoms in the ion, we multiply the oxidation number of iodine (by x) by 3.
Now, solving the equation:
-3 + x = -1
x = -1 + 3
x = +2
Therefore, the oxidation number of iodine in the I3- ion is +2.