Math

A company producing steel construction bars uses the function R(x) = -0.06x²+10.2x -50 to model the unit revenue in dollars for producing x bars. For what number of bars is the revenue at a maximum? What is the unit revenue at that level of production?

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  1. if you do calculus
    dR/dt = -0.12 x + 10.2
    = 0 for max or min
    x = 10.2 /0.12 = 85 bars
    unit rev for 85 bars = R(85) / 85

    If you do not know calculus, complete the square for x and R to find the vertex of
    -0.06x²+10.2x -50 = R

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  2. My course is College Algebra concepts. We are dealing with quadratic equations. I got the first part, but I am having a hard time with the second part of the question.
    x=-b/2a
    x=-10.2/2(-0.06)
    x=-10.2/(-0.12)=-(-85)=85
    x=85 bars
    So I would simply take R(85) / 85 giving me 1 or replace x with 85?
    R(85) = -0.06(85)^2+10.2(85) -50
    R(85)= -0.06(7225)+867 -50
    R(85)= -433.5+867 -50
    R(85)=383.5
    Sorry for all the quesions.
    Rebecca

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