Math

Given ABC with a = 7, b = 5, and mA= 19° , find the number of distinct solutions
I got 3 solutions

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  1. law of sines:
    a/SinA=b/SinB=c/SinC
    7/sin19deg=5/sinB
    sinB=5*sin19deg/7=.233
    B= arcsin.233=13.5 deg
    Now you have A, B, a, b.
    C=180-A-B
    now solve for c using law of sines.

  2. Your data illustrates the ambiguous case.
    How can you have 3 solutions ???

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