Suppose that it takes 10.0 h to drain a container of 5100 m3 of water. What is the "mass flow rate," in kilograms per second, of water from the container?
To find the mass flow rate of water, we need to know the volume flow rate and the density of water.
The volume flow rate is given by dividing the volume of water (5100 m^3) by the time it takes to drain it (10.0 h). First, we need to convert hours to seconds to have consistent time units: 10.0 hours * 3600 seconds/hour = 36000 seconds.
Volume flow rate = Volume of water / Time taken
Volume flow rate = 5100 m^3 / 36000 s
Volume flow rate = 0.1417 m^3/s
The density of water is approximately 1000 kg/m^3.
Now, to find the mass flow rate, we multiply the volume flow rate by the density.
Mass flow rate = Volume flow rate * Density
Mass flow rate = 0.1417 m^3/s * 1000 kg/m^3
Mass flow rate = 141.7 kg/s
Therefore, the mass flow rate of water from the container is 141.7 kilograms per second.
To find the mass flow rate of water from the container, we need to convert the volume of water into mass using the density of water. The formula for mass flow rate (ṁ) is given by:
ṁ = ρ * V
Where:
ṁ = mass flow rate
ρ = density of water
V = volume of water
The density of water is approximately 1000 kg/m^3.
Given:
Volume of water, V = 5100 m^3
Time, t = 10.0 h
To convert the time from hours to seconds, we multiply by 3600 (since there are 3600 seconds in one hour):
t = 10.0 h * 3600 s/h = 36000 s
Now, let's calculate the mass flow rate:
ṁ = 1000 kg/m^3 * 5100 m^3 / 36000 s
Simplifying the expression:
ṁ = (1000 * 5100) / 36000 kg/s
Calculating the value:
ṁ ≈ 141.67 kg/s
Therefore, the mass flow rate of water from the container is approximately 141.67 kilograms per second.
5100 m^3 of water has a mass of 5.1*10^6 kg. Divide that by 10 hours (expressed as seconds) for the mass flow rate in the units you want.
That's a very large container! More like an Olympic swimming pool.