The wavelength in air of the sound from a violin is 4.00x10⁻¹m. What is the frequency of vibration of the violin? (Ans: 850Hz)
frequency = speed / wavelength
speed of sound in air is ... 343 m/s
... it is dependent on barometric pressure, temperature, humidity, etc.
thanks for the correction
given that speed of air is 3.40x10²m/s
V/F = 0.4 m.
340/F = 0.4,
F = ?
To find the frequency of vibration of the violin, we need to use the equation:
speed = frequency × wavelength
Where:
- speed is the speed of sound in air, which is approximately 343 meters per second at room temperature;
- frequency is the unknown we're trying to find;
- wavelength is given as 4.00x10⁻¹ meters.
Rearranging the equation, we get:
frequency = speed / wavelength
Plugging in the values, we have:
frequency = 343 m/s / (4.00x10⁻¹ m)
To divide by a decimal in scientific notation, we need to convert it to standard notation. So, 4.00x10⁻¹ becomes 0.40.
frequency = 343 m/s / 0.40 m
Now, we can simply divide the two numbers:
frequency ≈ 857.5 Hz
So, the frequency of vibration of the violin is approximately 857.5 Hz.