A 1.0m³ block of ice floats in fresh water. 92% of its volume is below the surface of the water. What is the magnitude of the buoyancy force acting on the block?
what is the mass of .93*1m^3 of water?
mass=volume*density=1m^3*.931e3kg/m^3=930kg
so what is the force acting? 930kg*9.8N/kg=...wow
To find the magnitude of the buoyancy force acting on the block of ice, we can use Archimedes' principle, which states that the buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.
First, let's calculate the volume of the block of ice submerged in the water. We are given that 92% of the block's volume is submerged, so we multiply the total volume of the ice block (1.0m³) by 92%:
Volume submerged = 1.0m³ * 0.92 = 0.92m³
The buoyant force acting on the block is equal to the weight of the water displaced by the submerged portion of the block. The density of water is approximately 1000 kg/m³.
Buoyant force = Density of water * Volume submerged * Acceleration due to gravity
Buoyant force = 1000 kg/m³ * 0.92m³ * 9.8 m/s²
Simplifying the equation, we find:
Buoyant force = 900 kg * 0.92 * 9.8 m/s²
Buoyant force = 8009.6 N
Therefore, the magnitude of the buoyant force acting on the block of ice is approximately 8009.6 Newtons.