Detrmine the resultant force if two force a and b act an cobject f a is85n atangle of20degre to the horzontal a f b is 125at anle of 60 degree solve the resultant force ?5kb363d
an cobject f a is85n atangle of20degre to the horzontal a f b is 125at anle of 60 degree >> HUH?
Fr = 85[20o] + 125[60o].
X = 85*Cos20 + 125*Cos60 = 142.4 N.
Y = 85*sin20 + 125*sin60 = 137.3 N.
Fr = sqrt(X^2 + Y^2) = 197.8 N.
TanA = Y/X, A = 44o = Direction.
To solve for the resultant force, we need to break each force into its horizontal and vertical components, and then find the sum of these components.
1. Force A:
- Magnitude: 85 N
- Angle: 20 degrees to the horizontal
To find the horizontal component (Fx) of force A:
- Fx = Magnitude * cos(angle)
- Fx = 85 N * cos(20 degrees)
To find the vertical component (Fy) of force A:
- Fy = Magnitude * sin(angle)
- Fy = 85 N * sin(20 degrees)
2. Force B:
- Magnitude: 125 N
- Angle: 60 degrees to the horizontal
To find the horizontal component (Fx) of force B:
- Fx = Magnitude * cos(angle)
- Fx = 125 N * cos(60 degrees)
To find the vertical component (Fy) of force B:
- Fy = Magnitude * sin(angle)
- Fy = 125 N * sin(60 degrees)
Now we have the horizontal and vertical components for both forces. To find the resultant force (Fr), we need to sum the horizontal and vertical components separately:
Horizontal component (Rx):
- Rx = Fx of A + Fx of B
Vertical component (Ry):
- Ry = Fy of A + Fy of B
Finally, we can find the magnitude of the resultant force (R) using the Pythagorean theorem:
- R = sqrt(Rx^2 + Ry^2)
Plug in the values and perform the calculations to find the resultant force.