A recent survey determine the IQ score of a random selection of residents of Alaska. The accompanying relative frequency distribution table summarizes the results.
Identify the class width for the given relative frequency distribution.
IQ Score----Relative Frequency
50-69--------5%
70-89--------23%
90-109------46%
110-129-----19%
130-149-----7%
a. 19
b. 20
c. 19.5
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To identify the class width, we need to calculate the difference between the upper and lower boundaries of any one class interval.
Looking at the given frequency distribution, we can see that the classes are as follows:
1st class: 50-69
2nd class: 70-89
3rd class: 90-109
4th class: 110-129
5th class: 130-149
Taking the upper boundary of the 1st class (69) and subtracting the lower boundary of the 1st class (50), we get:
69 - 50 = 19
So, the class width for the given relative frequency distribution is 19.
Hence, the correct answer is option a. 19.
To identify the class width for the given relative frequency distribution, we need to find the difference between the upper class limit and the lower class limit of any interval.
Looking at the intervals in the table, the upper class limits are 69, 89, 109, 129, and 149.
The lower class limits are 50, 70, 90, 110, and 130.
To find the class width, we can subtract the lower class limit from the upper class limit of any interval.
For example, taking the second interval with an upper class limit of 89 and a lower class limit of 70:
89 - 70 = 19
So, the class width for this interval is 19.
We can verify this by checking any other interval in the table. The class width will remain the same.
Therefore, the class width for this relative frequency distribution is 19.
The correct answer is (a) 19.