Math: d is partly constant and partly varies with v when V=40 d=150 and when v=54 d=192
I don't understand
pls solve the maths
When 2 is added to a certain number and the sum was doubled, the results was 36 less than the original number multiplied by 4. Find the number
To find the relationship between d and v, we need to determine the constant part of d and the part that varies with v. Let's consider the given data points:
When V = 40, d = 150
When V = 54, d = 192
This tells us that when V increases by 14 (from 40 to 54), d increases by 42 (from 150 to 192). Therefore, the variable part of d increases by 42/14 = 3 for each additional unit of v.
Now, let's find the constant part of d. Notice that when v = 0, d is 150 + 0(3) = 150. Therefore, the constant part of d is 150.
Putting it all together, we have the relationship between d and v:
d = 150 + 3v
So, if you have a value for v, you can substitute it into the equation to find the corresponding value of d.