A train has an initial velocity of 44m/s-2 and acceleration of 4m/s-2 velocity after 10s is
V = Vo + a*t = 44 + 4*10 =
https://www.jiskha.com/questions/1775789/A-body-accelerate-uniformly-from-rest-at-2ms-2-calculate-it-s-velocity-after-travelling
Clearly you paid no attention to Steve!
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To find the velocity after 10 seconds, we can use the equation:
Final velocity (v) = Initial velocity (u) + (acceleration (a) * time (t))
Given:
Initial velocity (u) = 44 m/s
Acceleration (a) = 4 m/s^2
Time (t) = 10 s
Plugging in the values, we get:
v = 44 m/s + (4 m/s^2 * 10 s)
v = 44 m/s + 40 m/s
v = 84 m/s
So, the velocity after 10 seconds is 84 m/s.
To find the velocity of the train after 10 seconds, we can use the equation of motion:
v = u + at
Where:
v = final velocity
u = initial velocity
a = acceleration
t = time
Given:
u = 44 m/s
a = 4 m/s²
t = 10 s
Plugging the values into the equation, we get:
v = 44 + 4 * 10
v = 44 + 40
v = 84 m/s
Therefore, the velocity of the train after 10 seconds is 84 m/s.