A girl standing on a bridge drops a stone over the side of the bridge. The stone strikes the water below the bridge 5.00s after the stone is dropped.
When the stone hits the water, what is the displacement of the stone from the point where the stone was dropped?
To determine the displacement of the stone when it hits the water, we need to calculate the distance it travels vertically downwards during the 5.00 seconds. We can use the equation of motion for vertical free fall:
h = (1/2)gt^2
Where:
h = displacement (height or distance fallen)
g = acceleration due to gravity (approximately 9.8 m/s²)
t = time (5.00 seconds)
Substituting the given values into the equation, we have:
h = (1/2)(9.8 m/s²)(5.00 s)^2
h = (1/2)(9.8 m/s²)(25.00 s²)
h = 122.5 m
Therefore, the displacement of the stone from the point where it was dropped is 122.5 meters downwards.