A ball is dropped from the top of a building which is 39.2m above the level of the sidewalk.
How long does it take for the ball to reach the sidewalk?
hf=hi+vi*t-4.9t^2
0=39.2+0-4.9t^2
solve for time t.
To find the time it takes for the ball to reach the sidewalk, we can use a basic equation of motion. The equation we can use is:
h = 1/2 * g * t^2
Where:
- h is the height of the building (39.2m in this case),
- g is the acceleration due to gravity (approximately 9.8 m/s^2),
- t is the time it takes for the ball to reach the sidewalk (what we want to find).
By rearranging the equation, we have:
t = sqrt(2 * h / g)
Plugging in the given values, we can calculate the time it takes for the ball to hit the sidewalk:
t = sqrt(2 * 39.2 / 9.8)
t = sqrt(78.4 / 9.8)
t = sqrt(8)
Therefore, the time it takes for the ball to reach the sidewalk is approximately 2.83 seconds.