How many grams of sodium iodide, NaI, must be used to produce 88.1 g of iodine, I2
NaI = 23 + 127 = 150 grams/mol
2 mol NaI is therefore 300 g
I2 is 2*127 = 254 g/mol
2 NaI --> 2 Na + I2
88.1 /254 = mols I2
= mols 2Na = x/300
x = (300/254 )88.1
To determine the number of grams of sodium iodide, NaI, needed to produce 88.1 g of iodine, I2, we need to calculate the molar masses of both sodium iodide and iodine.
The molar mass of sodium iodide (NaI) can be found by adding the molar masses of sodium (Na) and iodine (I):
Na: 22.99 g/mol
I: 126.90 g/mol
Molar mass of NaI = 22.99 g/mol + 126.90 g/mol = 149.89 g/mol
Now, we can calculate the number of moles of iodine (I2) required to produce 88.1 g:
88.1 g / (molar mass of iodine) = 88.1 g / 253.80 g/mol ≈ 0.3474 mol
According to the balanced chemical equation, the ratio of moles of sodium iodide (NaI) to moles of iodine (I2) is 1:1.
Therefore, the number of moles of sodium iodide (NaI) required will also be approximately 0.3474 mol.
Finally, we can calculate the mass of sodium iodide (NaI) needed:
Mass of NaI = (number of moles of NaI) × (molar mass of NaI)
= 0.3474 mol × 149.89 g/mol
≈ 52.13 g
Approximately 52.13 grams of sodium iodide (NaI) must be used to produce 88.1 grams of iodine, I2.
To determine the amount of sodium iodide, NaI, needed to produce 88.1 g of iodine, I2, we need to calculate the stoichiometry of the reaction between NaI and I2.
The balanced chemical equation for the reaction between NaI and I2 is:
2 NaI + Cl2 → 2 NaCl + I2
The equation shows that 2 moles of NaI react to produce 1 mole of I2. To find the molar mass of NaI, we add the atomic masses of sodium (Na) and iodine (I).
Na: 22.99 g/mol
I: 126.90 g/mol
Molar mass of NaI:
Na: 22.99 g/mol
I: 126.90 g/mol
Molar mass of NaI = 22.99 + 126.90 = 149.89 g/mol
Now, we can calculate the number of moles of NaI required to produce 88.1 g of I2 using the molar mass of NaI:
Number of moles of NaI = Mass of I2 / Molar mass of NaI
Number of moles of NaI = 88.1 g / 149.89 g/mol
Finally, we can convert the number of moles of NaI to grams using its molar mass:
Mass of NaI = Number of moles of NaI * Molar mass of NaI
Therefore, the mass of sodium iodide, NaI, required to produce 88.1 g of iodine, I2, can be calculated using the above formula.