On his way off to college, Russell drags his bag 15.0 m from the door of his house to the car at a constant speed with a horizontal force of 95.0 N. How much work does Russell do to overcome the force of friction?
work=force*distance.
The work he did is the same as work done on friction.
but the answer in my book is 1430, and i got 1425
That's probably because of significant figures. 15.0 m and 95.0 N both have three significant figures. Therefore, the answer should also have three significant figures. 1425 rounded to three sigfigs is 1430.
thanks
To find the work done by Russell to overcome the force of friction, we can use the formula:
Work = Force * Distance * cos(theta)
In this case, the force applied by Russell is the horizontal force of 95.0 N, the distance is 15.0 m, and theta represents the angle between the force and the displacement. Since the displacement is horizontal and the force applied is also horizontal, the angle between them is 0 degrees or cos(0) = 1.
Substituting the given values into the formula:
Work = 95.0 N * 15.0 m * 1
Work = 1425 J
Therefore, Russell does 1425 J of work to overcome the force of friction.