Consider the reaction:P4 (s)+ 6 Cl2 (g) = 4PCl3(g)
Delt H = -1230 kJ
How much heat is released when 52.5 of Cl2 (g) reacts with an excess of P4 (s)?

I tried the question and got -910.8 kJ and the answer is suppose to be -/+ 152 kJ.

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  1. Moles Cl2=52.5/70.9=.74 moles
    heat released= .74/6*1230=-152 kJ

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  2. but....0.74/6*1230= 0.74/7380=0.000100271 moles..

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  3. (0.74/6)1230=152kj

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