1.) If the penny is at a radius of 6.00 cm spinning at a speed of 3.50 rad/sec. What is the centripetal acceleration of the penny in m/s2? Enter your answer to three significant figures.
Ac = R omega^2
R = 0.06 meter
omega = 3.5
That assumes you want Ac at the rim of the penny.
linear speed: 0.2100
centripetal acceleration: 0.7350
tangential acceleration: 0.0132
How to find total acceleration in m/s^2?
they are perpendicular
|A| = sqrt (At^2 + Ac^2)
To calculate the centripetal acceleration of an object, we need to use the formula:
a = r * ω^2
Where:
a = centripetal acceleration
r = radius
ω = angular velocity (in radians per second)
Given:
r = 6.00 cm = 0.06 m (since 1 cm = 0.01 m)
ω = 3.50 rad/sec
Substituting the given values into the formula, we have:
a = 0.06 * (3.50)^2
Now, let's solve it:
a = 0.06 * 12.25
a ≈ 0.735 m/s^2
Therefore, the centripetal acceleration of the penny is approximately 0.735 m/s^2.