Lisa brought half of her savings to the bakery and bought 12 croissants for $14.20. The amount of money she brings home with her is more than $2. Use an inequality to find how much money she had in her savings before going to the bakery. (Write the inequality that represents the situation and solve it.)
x/2 - 14.20 > 2.00
Let's say Lisa had x dollars in her savings before going to the bakery.
According to the given information, she brought half of her savings (x/2) to the bakery and bought 12 croissants for $14.20.
The amount of money she brings home with her is more than $2. Therefore, we can set up the following inequality:
(x/2) - 14.20 > 2
Now, let's solve the inequality:
(x/2) > 2 + 14.20
(x/2) > 16.20
Multiplying both sides by 2 to isolate x:
x > 32.40
Therefore, Lisa had more than $32.40 in her savings before going to the bakery.
To find how much money Lisa had in her savings before going to the bakery, we can set up an inequality.
Let's assume the amount of money Lisa had in her savings before going to the bakery is represented by "x" dollars.
Lisa brought half of her savings to the bakery, which means she had (x/2) dollars with her. She bought 12 croissants for $14.20.
Since Lisa's savings after the purchase is more than $2, we can write the inequality as:
(x/2) - 14.20 > 2
To solve this inequality, we can start by isolating the term with "x" on one side:
(x/2) > 2 + 14.20
Simplifying the right side:
(x/2) > 16.20
To get rid of the fraction, we can multiply both sides of the inequality by 2:
2 * (x/2) > 2 * 16.20
This simplifies to:
x > 32.40
So, the inequality that represents the situation is x > 32.40.
Therefore, Lisa had more than $32.40 in her savings before going to the bakery.