A bomb of mass 5kg explosed into equal fragment.at what angle these fragments fly apart. ?
The momentum before = the momentum after
so if there are two equal mass pieces
they have to fly apart at the same speed directly
away from each other so the final momentum
sums to zero. 180 degrees
To determine the angle at which the fragments of a bomb with a mass of 5 kg explode, we need more information. The angle at which the fragments fly apart depends on several factors, such as the type of explosion, the direction of the explosive force, and the shape and location of the bomb fragments.
If the explosion is symmetrical and exerts force equally in all directions, the fragments would ideally disperse equally in all directions, resulting in a spherical pattern. However, in most cases, the explosive force is not symmetric, and the fragments are not evenly distributed.
If the bomb fragments into two equal parts, it suggests a binary fission-like explosion, where the fragments separate into two halves along a central line. In this scenario, the fragments would fly apart at an angle of 180 degrees from each other, resulting in a straight line (opposite directions).
If the bomb fragments into more than two parts, the angle at which they fly apart depends on the specific explosive force and the geometry of the fragments. Without specific information on these factors, it is challenging to determine the exact angle at which the fragments disperse.
To obtain a more accurate answer, it would be necessary to consult specific data related to the bomb, explosive material, and the conditions under which the explosion occurred.