The specific heat of water is 4.184J/gc and that of aluminum is 0.897J/gc which substance will show a larger increase in temperature upon the addition of 100J of heat to 100g the aluminum or the water
heat in = mass x specific heat x delta T
q = mc(delta T)
100 = 100 x 4.184 x delta T.
Substitute and solve for dT.
Substitute for Al and calculate dT.
Which dT is larger?
Don’t know how to put the calculation
To determine which substance will show a larger increase in temperature when 100J of heat is added, we can compare the heat capacity of aluminum and water.
The heat capacity is calculated by multiplying the specific heat by the mass of the substance. Let's calculate the heat capacity for aluminum and water:
For aluminum:
Heat capacity = specific heat * mass
Heat capacity = 0.897J/g°C * 100g = 89.7J/°C
For water:
Heat capacity = specific heat * mass
Heat capacity = 4.184J/g°C * 100g = 418.4J/°C
Comparing the heat capacities, we can see that water has a larger heat capacity (418.4J/°C) compared to aluminum (89.7J/°C).
Therefore, when 100J of heat is added, water will show a larger increase in temperature compared to aluminum.
To determine which substance, aluminum or water, will show a larger increase in temperature upon the addition of 100J of heat to 100g, we need to calculate the change in temperature using the specific heat equation.
The equation for calculating the change in temperature using specific heat is:
q = m * c * ΔT
where:
q is the amount of heat energy absorbed or released
m is the mass of the substance
c is the specific heat capacity of the substance
ΔT is the change in temperature
For aluminum:
q = 100J (given)
m = 100g (given)
c = 0.897J/g°C (specific heat of aluminum)
Now we can rearrange the equation to solve for ΔT:
ΔT = q / (m * c)
Substituting the given values:
ΔT(aluminum) = 100J / (100g * 0.897J/g°C) = 1.115°C
For water:
q = 100J (given)
m = 100g (given)
c = 4.184J/g°C (specific heat of water)
Similarly, substituting the values into the equation:
ΔT(water) = 100J / (100g * 4.184J/g°C) = 0.238°C
Comparing the two values, we can see that the change in temperature for aluminum (1.115°C) is larger than that for water (0.238°C). Therefore, aluminum will show a larger increase in temperature upon the addition of 100J of heat to 100g compared to water.