Mishelle is 7 years younger than Paul. Given that the sum of their ages is 29, find their ages
P = M + 7
P + M = 39
Substitute M+7 for P in second equation, solve for M, then use first equation to find P.
Paul is X yrs. old.
Mishelle is X - 7.
x + (x-7) = 29.
X = ?
x - 7 = ?.
To find their ages, let's set up an equation using the information given.
Let's assume Mishelle's age is x. Since Mishelle is 7 years younger than Paul, Paul's age would be x + 7.
The sum of their ages is 29, so we can write the equation as:
x + (x + 7) = 29
Now, we can solve the equation to find the value of x (Mishelle's age).
Combining like terms, we get:
2x + 7 = 29
Subtracting 7 from both sides, we have:
2x = 22
Next, we divide both sides by 2 to isolate x:
x = 11
Now that we know Mishelle's age is 11, we can find Paul's age by adding 7:
Paul's age = 11 + 7 = 18
Therefore, Mishelle is 11 years old and Paul is 18 years old.