Hello Ms.Sue. Can you check this to make sure I did it correctly. Thank you in advance for the help.
What is the slope of the line 3x + 4y = 1?
4y=3x-1
y=(=3/4)time X-1/4
Slope, m=3/4
You made an error in subtracting 3x from both sides
3x + 4y = 1
4y = -3x + 1
divide every term by 4
y = -3/4 x + 1/4 , so the slope is -3/4
here is a nice quick way:
if your equation is of the form Ax + By + C = 0
the slope is -A/B
so for 3x + 4y - 1 = 0 , the slope = -3/4
Thank you Reiny for correcting my error.
Hello! I'd be happy to help you with your question.
To find the slope of a line, we can rearrange the given equation into slope-intercept form (y = mx + b), where m represents the slope.
Let's break down the steps together:
1. Start with the equation: 3x + 4y = 1
2. To isolate the y-term, subtract 3x from both sides of the equation: 4y = -3x + 1
3. Divide every term by 4 to solve for y: (4y/4) = (-3x + 1)/4
4. Simplify further: y = (-3/4)x + 1/4
Now that we have the equation in slope-intercept form, we can see that the slope (m) is -3/4.
Therefore, it seems that you have made a mistake. The correct slope for the line 3x + 4y = 1 is -3/4, not 3/4.
I hope this explanation helps you understand how to find the slope of a line equation. Let me know if you have any more questions!