how can i simplify this more its for the following problem:
Problem #22
solve by using the quadratic formual.
5x^2-4x+1=0
this is where i am but i do not know how to go further.
x = (4 (+/-) sqrt (-4))/(10)
Problem #23
Solve by completing the square.
4x^2+2x-3=0
i started using the quadratic formula.
but i am up to this point
x = (-2 (+/-) sqrt (-44))/(8)
in #22 you are right so far.
Have you learned about imaginary or complex numbers.
If not, at this point you would say,
"there is no real solution"
for #23 you are not supposed to use the quadratic equation.
Use the method I showed you in the last post to you, but you have to divide all terms by 4 to get x^2 at the front
x^2 + 1/2 x = 3/4
now take 1/2 of the 1/2 which is 1/4, square that and add 1/16 to both sides of the equation to keep the equality.
let me know what your got.
i don't know what you mean half of the half but how do know to take that half.and where did you get the 1/16
can you show me.
write down that step of what you refer to please.
1/2 of 1/2 = 1/2 * 1/2 = 1/4
If you have half a pizza and you take half of that, how much pizza do you have?
I had to square 1/4 ---> (1/4)(1/4)= 1/16
I need help NOW because report cards are comming out tommorow and I have a F in math
I'm here to help! Let's go step by step to simplify the equation using completing the square method for Problem #23.
1. Start with the equation:
4x^2 + 2x - 3 = 0
2. Divide all terms by 4 to get x^2 as the first term:
x^2 + (1/2)x - 3/4 = 0
3. Now, we want to complete the square by adding and subtracting a constant term to the equation. To do this, take half of the coefficient of x (which is 1/2) and square it. The result is (1/2)^2 = 1/4.
4. Add and subtract 1/4 to both sides of the equation:
x^2 + (1/2)x + 1/4 - 1/4 - 3/4 = 0
5. Rearrange the terms:
(x + 1/2)^2 - 4/4 - 3/4 = 0
6. Simplify the equation:
(x + 1/2)^2 - 7/4 = 0
Now, the equation is in the form (x + h)^2 = k, where h and k are constants.
By completing the square, we have transformed the equation into a perfect square trinomial. The constant term (-7/4) can be considered as k, and the coefficient of x (1/2) is used to determine the value of h.