# Physics

A tennis ball with a speed of 26.3 m/s is moving perpendicular to a wall. After striking the wall, the ball rebounds in the opposite direction with a speed of 13.8338 m/s. If the ball is in contact with the wall for 0.00998 s, what is the average acceleration of the ball while it is in contact with the wall? Take “toward the wall” to be the positive direction. Answer in units of m/s2.

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1. force*time=mass*changeinVelocity
= mass*(13.8338+26.3)=mass*(40.1)
but force= mass*acceleration
so acceleration= 40.1/.00998 m/s^2

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