2x-3y=17 and 5y=-11 and Y show me how to figure out what is the value of x and y?
I think you can just add the two equations together.
2x-3y-17 = 0, and 5y + 11 = 0. Therefore, the 2 Eqs. are equal:
2x - 3y - 17 = 5y + 11,
2x - 8y = 28,
x - 4y = 14,
X = 4y + 14
2(4y+14) = 17,
8y + 28 = 17,
Y = -11/8.
Plug the value of Y into Eq1 and solve for X.
Correction:
2(4y+14)-3y = 17,
8y+28 - 3y = 17,
5y = -11,
Y = -11/5.
In Eq1, replace Y with -11/5 and solve for X.
To find the values of x and y, you can use the given equations and solve them simultaneously.
Let's start by solving for y using the second equation:
5y = -11
To isolate y, divide both sides of the equation by 5:
y = -11/5
Now that we have the value of y, we can substitute it into the first equation:
2x - 3(-11/5) = 17
Next, distribute the -3 to -11/5:
2x + 33/5 = 17
To isolate x, subtract 33/5 from both sides of the equation:
2x = 17 - 33/5
Now, find a common denominator to subtract the fractions:
2x = (85/5) - (33/5)
Simplify:
2x = 52/5
To isolate x, divide both sides of the equation by 2:
x = (52/5) / 2
Simplify further:
x = 52/10
Reduce the fraction:
x = 26/5
So, the values of x and y are x = 26/5 and y = -11/5, respectively.