the outer rectangle is 32 cm by 20 cm.the inner rectangle is 26 cm by 14 cm .all measurement are given to the nearest centimetres.calculate the lower bound of the perimeter of the outer rectangle.
The outer rectangle could be as small as 31.5 by 19.5, so the lower bound on the perimeter would be
2(31.5+19.5) = 102 cm
Hello steve , I believe you answered this before.
Insert <, >, or = to make the sentence true.
-1/3 -2/5
A.)=
B.)>
C.)<
-1/3 = -0.333
-2/5 = -0.400
so, what do you think? If you're not sure, plot them both on the number line, and see where they lie.
To calculate the lower bound of the perimeter of the outer rectangle, we need to consider the lower bounds of the given measurements.
The outer rectangle has dimensions of 32 cm by 20 cm. Since all measurements are given to the nearest centimeters, we assume the actual values could be as low as 31.5 cm and 19.5 cm respectively.
To find the lower bound of the perimeter, we add the lower bound values of the two sides of the rectangle:
Lower Bound Perimeter = (Lower Bound of Length + Lower Bound of Width) × 2
= (31.5 cm + 19.5 cm) × 2
= 51 cm × 2
= 102 cm
Therefore, the lower bound of the perimeter of the outer rectangle is 102 centimeters.