Question

A tug tows a small boat with a rope inclined upwards at 30 degrees to the horizontal. The tension in the string is 2000 newton. What is the force tending to raise the boat out of water

Answer 1

horizontal tow force = 2000 cos 30

vertical up force = 2000 sin 30 = 1000 Newtons

Answer 2

Answer

Answer 3

Ans

Answer 4

=10

Answer 5

[AI-generated answer — Explain Bot]

To find the force tending to raise the boat out of the water, we need to break down the tension in the rope into its vertical and horizontal components. The vertical component of the tension will be the force tending to raise the boat out of the water.

To do this, we need to use trigonometry. Since the rope is inclined at an angle of 30 degrees to the horizontal, we can use the sine function to find the vertical component of the tension:

Vertical component = Tension * sin(angle)

In this case, the tension is given as 2000 Newtons and the angle is 30 degrees. Plugging these values into the equation, we get:

Vertical component = 2000 * sin(30°)

Now, we can calculate the vertical component of the tension:

Vertical component = 2000 * 0.5
= 1000 Newtons

Therefore, the force tending to raise the boat out of the water is 1000 Newtons.