Question: How do you calculate the molecular weight of something like: A_xB_yC where x=1, and y=0.5?
Attempt to the soln:
Let Molecular Weight be MW:
Is it then: MW OF A_xB_yC [x=1, y=0.5] = (MW of A)x1 + (MW of B)x0.5 + (MW of C)? Am I doing this correctly?
No. You have to have whole numbers as subscripts.
A2BC2
then MW = 2*A+B+2*C
Even when those individuals elements (A, B and C) were mixed with that composition??
it is the same composition1:.5:1 is the same as 2:1:2 MW reflects the sum of the atomic weights in a MOLE of the substance, not how much you made.
Yes, you are on the right track to calculate the molecular weight of A_xB_yC when x=1 and y=0.5. The formula you provided is correct.
To calculate the molecular weight, you need to know the atomic weights of elements A, B, and C. You can find the atomic weights either from a periodic table or an online database.
The molecular weight is calculated by multiplying the atomic weight of each element by its respective subscript in the formula, and then adding them all together.
In your case, you have x=1 for A and y=0.5 for B. Let's assume the atomic weights for A, B, and C are MW_A, MW_B, and MW_C, respectively.
So, the molecular weight of A_xB_yC is:
MW(A_xB_yC) = (MW_A × x) + (MW_B × y) + (MW_C)
Substituting x=1 and y=0.5 into the equation, you get:
MW(A_xB_yC) = (MW_A × 1) + (MW_B × 0.5) + (MW_C)
Therefore, your formula MW(A_xB_yC) = (MW of A)x1 + (MW of B)x0.5 + (MW of C) is correct, assuming you have accurate values for the atomic weights of A, B, and C.