science

A man pulls a box with a force of 70N along the positive Y-axis, while a boy pulls it with a force of 50N, making an angle of 80°counter clockwise with the positive Y-axis.
(1)In what direction should the second boy apply a force of 60N so that the box will move along the positive Y-axis? Hint;two values are possible

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  1. well,
    along the x axis: You want the net force in that direction to be zero.

    70Sin0deg+50sin80+60sinTheta=0
    sinTheta=-50sin80deg/60= -0.820673128
    Theta=-(55.1522333 deg) or -(-55.1522333 deg+180deg) or -124.8deg

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    bobpursley
  2. F1 = 70[90o] CCW from +x-axis
    F2 = 50[170o] CCW from +x-axis.
    F3 = 60[Ao] from +x-axis.

    Sum of hor. components = 0:
    70*Cos90 + 50*Cos170 + 60*Cos A = 0.
    60*Cos A = 49.2.
    A = 34.9 degrees.

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  3. 50*sin280 = -60*sin A,
    - 49.24 = -60*sin A,
    sin A = 49.2/60,
    A = 55.1o CW from +Y-axis = 34.9o CCW from +X-axis.

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