chemistry

A 0.509 g sample pure platinum metal was reacted with hcl to form 0.889 g of a compound containing only platinum and chlorine?

asked by Sofia
  1. So the product must be of the form PtCln, and the question is what is n, the ratio of the chloride to platinum.
    Moles of Pt: .509/atomicmassPt =.509/198=.00257
    moles of Cl: (.889-.509)/atomicmassCl=.38/35.45=.0107

    dividing each by the lowest, to get the ratio
    Cl: .107/.00257=4.2
    Pt:; .00257/.00257=1

    Empirical formula: PtCl4

    posted by bobpursley

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