please show me how to solve this
1. A bus travels 280 km south along a straight path with an average velocity of 88 km/h to the south. the bus stops for 24 min. then, it travels 210 km south with an average velocity of 75 km/h to the south
a. how long does the total trip last?
answer=6.4 h
b. what is the average velocity for the total trip?
answer=77 km/h to the South
thanks to whoever helps=]
a. Add the times requred for each of the two driving intervals, and add 24 minutes (0.4 hours) to that sum.
For each driving inteveral, use the reationship
time = distance)/(average speed
The sum will be the total driving and waiting time. Call it T.
b. Divide (280 + 210)km by T
That is how to do it. You do the numbers.
ok thanks
so is this what i do:
280+210[how much they traveled]=490
then add .4 hours = 490.4
then :
T=490.4[distance]/average speed so 81.5?
my answer comes out 6.01 hours
i think im still doing something wrong
the last post was by y912f not mysterychicken
You did not follow my instructions. You cannot add distance (km) to time (hours) in physics. It makes no sense.
The total time is
T = 280/88 + 0.4 + 210/75 = 6.38 hours
To solve part a, we need to find the total time of the trip. We can find the time for each leg of the trip and then add them together.
1. For the first leg of the trip, the bus travels 280 km with an average velocity of 88 km/h. We can use the formula time = distance/velocity to find the time taken for this leg.
time = 280 km / 88 km/h = 3.18 hours
2. The bus then stops for 24 minutes, which is equivalent to 24/60 = 0.4 hours.
3. For the second leg of the trip, the bus travels 210 km with an average velocity of 75 km/h. Again, we can use the time = distance/velocity formula.
time = 210 km / 75 km/h = 2.8 hours
Now, let's add up the times for each leg of the trip to find the total time:
Total time = time for first leg + time for stop + time for second leg
Total time = 3.18 hours + 0.4 hours + 2.8 hours = 6.38 hours
Rounded to one decimal place, the total time of the trip is approximately 6.4 hours.
To solve part b, we need to find the average velocity for the entire trip. We can use the formula average velocity = total distance / total time.
1. The total distance is the sum of the distances traveled in each leg of the trip.
Total distance = 280 km + 210 km = 490 km
2. We already found the total time of the trip to be 6.4 hours.
Now, let's use the formula for average velocity:
Average velocity = total distance / total time
Average velocity = 490 km / 6.4 hours
Using a calculator, we find that the average velocity is approximately 76.6 km/h.
Since the bus is traveling south, the average velocity for the total trip can be rounded to 77 km/h south.
So the answers to the questions are:
a. The total trip lasts approximately 6.4 hours.
b. The average velocity for the total trip is approximately 77 km/h to the south.