Equivalent weight of H3PO4 for the given reaction, H3PO4 + Ca(OH)2 = CaHPO4 + 2H2O is?
To determine the equivalent weight of H3PO4 in the given reaction, we need to consider the stoichiometry of the reaction.
The balanced chemical equation is:
H3PO4 + Ca(OH)2 → CaHPO4 + 2H2O
From the equation, we can see that 1 mole of H3PO4 reacts with 1 mole of Ca(OH)2 to form 1 mole of CaHPO4 and 2 moles of H2O.
The equivalent weight is defined as the molecular weight of a substance divided by the number of equivalents. In the case of H3PO4, it is a triprotic acid, meaning it can donate 3 moles of H+ ions.
The molecular weight of H3PO4 is:
1(1.01 g/mol for H) + 3(16.00 g/mol for O) + 1(31.0 g/mol for P) = 98.0 g/mol
Since H3PO4 donates 3 moles of H+ ions, the equivalent weight is calculated by dividing the molecular weight by 3:
98.0 g/mol / 3 = 32.67 g/equiv
Therefore, the equivalent weight of H3PO4 for the given reaction is approximately 32.67 grams per equivalent.
To find the equivalent weight of H3PO4 for the given reaction, we need to first understand what equivalent weight means.
The equivalent weight (or equivalent mass) of a substance is the amount of the substance that can react with or replace one equivalent of hydrogen ions (H+) or hydroxide ions (OH-).
In the given reaction, H3PO4 + Ca(OH)2 = CaHPO4 + 2H2O, we can see that one mole of H3PO4 reacts with one mole of Ca(OH)2 to form one mole of CaHPO4 and two moles of H2O.
The reaction shows that the stoichiometric ratio between H3PO4 and Ca(OH)2 is 1:1. This means that one equivalent of H3PO4 corresponds to one equivalent of Ca(OH)2.
To calculate the equivalent weight of H3PO4, we need to find the molar mass of H3PO4 and divide it by the number of equivalents.
The molar mass of H3PO4 is:
1 hydrogen atom (H) weighs 1 g/mol
3 hydrogen atoms (H) in H3PO4 weigh 3 g/mol
1 phosphorus atom (P) weighs 31 g/mol
4 oxygen atoms (O) in H3PO4 weigh 16 g/mol each, totaling 64 g/mol
So the molar mass of H3PO4 is 3 + 31 + 64 = 98 g/mol.
Since one mole of H3PO4 reacts with one mole of Ca(OH)2, the number of equivalents of H3PO4 is equal to the number of equivalents of Ca(OH)2, which is 1.
Therefore, the equivalent weight of H3PO4 for this reaction is:
Equivalent weight = Molar mass / Number of equivalents
= 98 g/mol / 1
= 98 g/mol
So, the equivalent weight of H3PO4 for the given reaction is 98 g/mol.