A is a solution of trioxonitrate (v)acid, HNO3 of unknown concentration.B is standard solution of sodium hydroxide containing 4.00g per dm3 of solution. 25 cm3 portion solution B required an average of 24.00cm3 of solution A for neutralization using 2drops of methyl orange 1 write a balanced equation for the reaction 2 calculate the concentration of solution B in moles per dm3 3 calculate the concentration of solution A in moles per dm3 4 calculate the concentration in G/dm3 of HNO3 in solution (A H=1, N=14, O=16,Na=23)
Moles of base per liter= 4/40
Molarity of base= 0.1M
Molaritybase*volumebase=MolarityAcid*volumeacid (both are monoprotic)
0.1*25cm^3=Molarityacid*24cm^3.
molarity acid=.1*25/24
massacid/liter= 40*.1*25/24=4.17 grams/dm^3
A is a solution of trioxonitrate(v) acid, HNO3, of unknown concentration. B is standard solution of sodium hydroxide containing 4.00g per dm3 of solution. 25cm3 portions solution B required an average of 24.00cm3 of solution A for neutralization, using 2drops of methyl orange.
a: write a balanced equation for the reaction?
b:Calulate the concentration of solution B in moles per dm3 ?
c: calculate the concentration of solution A in moles per dm3
d: calculate the concentration in g/dm3 of HNO3 in solution A. (H=1, N=14, O=16, Na=23
The IUPAC name for HNO3 is nitric acid and not that weirdo name you wrote.
Yes
1. Balanced equation for the reaction:
HNO3 + NaOH → NaNO3 + H2O
2. Calculation of the concentration of solution B (NaOH) in moles per dm3:
Given that the solution B contains 4.00g per dm3 of NaOH, we need to find the molar mass of NaOH first.
The molar mass of NaOH = 23 + 16 + 1 = 40 g/mol
Now, we can calculate the concentration of solution B:
Concentration = mass/volume
Concentration = 4.00g/dm3 / (40 g/mol)
Concentration = 0.10 mol/dm3
Therefore, the concentration of solution B (NaOH) is 0.10 moles/dm3.
3. Calculation of the concentration of solution A (HNO3) in moles per dm3:
Since 24.00 cm3 of solution A is needed to neutralize 25 cm3 of solution B, we can assume the volume of solution A to be 24.00 cm3.
Now, we need to calculate the concentration of solution A.
Concentration of solution A = 0.10 mol/dm3 (since they neutralize each other)
Therefore, the concentration of solution A (HNO3) is also 0.10 moles/dm3.
4. Calculation of the concentration of HNO3 in solution A in g/dm3:
To calculate the concentration of HNO3 in g/dm3, we need to find the molar mass of HNO3.
The molar mass of HNO3 = (1 * 1) + (14 * 1) + (16 * 3) = 63 g/mol
Now, we can calculate the concentration:
Concentration = moles/volume
Concentration = 0.10 mol/dm3 * 63 g/mol
Therefore, the concentration of HNO3 in solution A is 6.3 g/dm3.
1. To write a balanced equation for the reaction, we need to determine the chemical equation based on the given information. Since solution B is a standard solution of sodium hydroxide (NaOH) and solution A is a trioxonitrate (V) acid (HNO3), the reaction can be represented as follows:
HNO3 + NaOH -> NaNO3 + H2O
2. To calculate the concentration of solution B in moles per dm3, we need to use the given information that there are 4.00g of NaOH per dm3 of solution B. The molar mass of NaOH is 23 + 16 + 1 = 40g/mol. Therefore, the number of moles of NaOH per dm3 is calculated as:
(4.00g / 40g/mol) = 0.10 mol/dm3
So, the concentration of solution B is 0.10 mol/dm3.
3. To calculate the concentration of solution A in moles per dm3, we can use the volume and concentration of solution B used for neutralization. We have the average volume of solution A used for neutralization as 24.00 cm3, which is equivalent to 0.024 dm3. Since the reaction is 1:1 between HNO3 and NaOH, the number of moles of solution A is the same as the number of moles of solution B used. Therefore, the concentration of solution A is:
0.10 mol/dm3
So, the concentration of solution A is 0.10 mol/dm3.
4. To calculate the concentration of HNO3 in solution A in g/dm3, we need to convert the concentration in moles to grams. The molar mass of HNO3 is calculated as follows:
(1 * 1) + (14 * 1) + (16 * 3) = 1 + 14 + 48 = 63g/mol
Now, we can calculate the concentration of HNO3 in g/dm3 by multiplying the concentration in moles per dm3 by the molar mass of HNO3:
0.10 mol/dm3 * 63 g/mol = 6.3 g/dm3
So, the concentration of HNO3 in solution A is 6.3 g/dm3.