Okay so, If i were to mix the following letters M,A,T,H,E,M,A,T,I,C,A,L, thoroughly. Then, draw one letter without looking What would be the probability?
I think its 1/12 or 5/12 but im not sure.
You mix the letters M, A, T, H, E, M, A, T, I, C, A, and L thoroughly. Without looking, you draw one letter. Find the probability P(A). Write the probability as:
a. a fraction in simplest form
b. a decimal
c. a percent
There are a total of 12 letters. Out of these, there are 4 A's. So, the probability of drawing an A is:
a. P(A) = 4/12 = 1/3 (fraction in simplest form)
b. P(A) = 0.3333 (rounded to four decimal places)
c. P(A) = 33.33% (rounded to two decimal places)
To find the probability of drawing a specific letter from a set of letters, you need to know the total number of possible outcomes and the number of favorable outcomes.
In this case, there are a total of 13 letters: M, A, T, H, E, M, A, T, I, C, A, L, and an extra M. Since we are assuming the letters are mixed thoroughly, we can treat all the letters as separate entities.
Therefore, the total number of possible outcomes is 13.
Now, to find the number of favorable outcomes, we need to determine how many times the desired letter appears in the set. In this case, the desired letter is any of the 12 individual letters (excluding the extra M). Since each letter appears only once, there are 12 favorable outcomes.
The probability can then be calculated as the number of favorable outcomes divided by the total number of possible outcomes:
Probability = Favorable outcomes / Total outcomes
Probability = 12 / 13
Therefore, the probability of drawing any specific letter from the set is 12/13, not 1/12 or 5/12.