Find an equation in point-slope form for a line having the slope of m=1/6 and containing the point (-7,-3).
(y-y1)=m(x-x1) you are given m, and x1=-7 and y1=-3.
Go for it.
(Y1-y)/(X1-x) = 1/6
(-3-y)/(-7-x) = 1/6
-x-7 = -18-6y
18+6y = x+7
6y = x - 11
Thank you
To find an equation in point-slope form for a line, you need to know the slope of the line and one point that it passes through. In this case, the slope (m) is given as 1/6 and the point is (-7, -3).
The point-slope form equation is given as:
y - y1 = m(x - x1)
Where (x1, y1) is the given point, and m is the slope.
Substituting the values, we have:
y - (-3) = 1/6(x - (-7))
Simplifying further:
y + 3 = 1/6(x + 7)
This is the equation in point-slope form for a line with slope 1/6 and passing through the point (-7, -3).