Chemistry

a hydrocarbon is burnt completely in excess oxygen. it is found that 1.00g of the hydrocarbon gives 2.93g carbon dioxide and 1.80g water. find the empirical formula of the hydrocarbon (H=1,C=12,O=16)

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asked by Henry
  1. break up the carbon dioxide to C and O
    2.93g>>(12/44)*2.95=.80gC;
    break up the water into H and O
    1.80g>>1.8*(2/18)=.2gH;

    now total them up, change to moles
    C=,8g=.8/12=.066moles
    H=.2g=.2/1= .2 moles
    Notice that the sum of H and C=1.0g, so all O was atmospheric
    now divide by the least of the above (.066)
    C=1
    H=.2/.066=3
    empirical: CH3

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    posted by bobpursley

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