Math

Sqr of 3c² over the sqr of 27

√ ̅3c²
---------
√ ̅27

√27 ∙ √3

√ ̅75 - 4√ ̅75

(√3 + √2)²

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1. Hey, you try first, for example:
(√3 + √2)²
well, (a+b)^2 = a^2 + 2 a b + b^2
so
(√3 + √2)² = 3 + 2√6 + 2
= 5 + 2√6

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