1.Identify the type of isomer (structural, geometric, or optical) each of the following pairs represents.
A. CHBrClF and CHBrFCl
B. n-butane and 2-methylpropane
C. trans-2-pentene and cis-2-pentene
For A I think it would be Geometric
For B I think it would be Optional
And for C I think it would also be Optional
Go to the blackboard and write 50 times OPTICAL, this assignment is not OPTIONAL.
B I disagree, C is the O word your are supposed to be writing at the blackboard.
None are right.
Go to Google and type in three separate times as
optical isomers, structural isomer, geometric isomer
To identify the type of isomer for each pair, let's go through the definitions of the different types of isomers:
1. Structural Isomer: These isomers have the same molecular formula but differ in the arrangement of atoms within the molecule. For example, they may have different branching patterns, functional groups, or connectivity.
2. Geometric Isomer: These isomers have the same molecular formula, connectivity, and order of attachment but differ in the arrangement of atoms or groups around a double bond or a ring. They are also known as cis-trans isomers.
3. Optical Isomer: These isomers are non-superimposable mirror images of each other and are known as enantiomers. They have the same connectivity and arrangement of atoms but differ in their three-dimensional arrangement.
Now let's analyze each pair:
A. CHBrClF and CHBrFCl:
Since the order of attachment of the atoms in both compounds is the same, and there are no double bonds or rings involved, these compounds are examples of structural isomers.
B. n-butane and 2-methylpropane:
Both n-butane and 2-methylpropane have the same molecular formula (C4H10) and differ only in the arrangement of carbon atoms. These compounds are also examples of structural isomers.
C. trans-2-pentene and cis-2-pentene:
Both trans-2-pentene and cis-2-pentene have the same molecular formula (C5H10) and the same arrangement of carbon atoms. However, they differ in the arrangement of atoms around the double bond. These compounds are examples of geometric isomers.
Therefore, the correct answers are:
A. Structural isomer
B. Structural isomer
C. Geometric isomer