A student weighed a sample of KHP and found it weighed 0.9803g. The titration of this KHP required 23.45 mL of base (NaOH). Calculate the molarity of the base.

To calculate the molarity of the base (NaOH), we need to use the formula:

Molarity (M) = (moles of solute) / (volume of solution in liters)

First, let's calculate the moles of KHP (solute). The molar mass of KHP is needed for this calculation, and it can be calculated by summing the atomic masses of the elements in KHP:

KHP (Potassium Hydrogen Phthalate) = K(C8H4O4)

Molar mass of KHP = (atomic mass of potassium) + (8 * atomic mass of carbon) + (4 * atomic mass of hydrogen) + (4 * atomic mass of oxygen)

Using the periodic table, we find:

atomic mass of potassium (K) = 39.10 g/mol
atomic mass of carbon (C) = 12.01 g/mol
atomic mass of hydrogen (H) = 1.01 g/mol
atomic mass of oxygen (O) = 16.00 g/mol

Molar mass of KHP = (39.10) + (8 * 12.01) + (4 * 1.01) + (4 * 16.00)
= 204.22 g/mol

Now, we can calculate the moles of KHP:

moles of KHP = (mass of KHP) / (molar mass of KHP)
= 0.9803 g / 204.22 g/mol

Next, we need to convert the volume of the solution from milliliters to liters:

volume of solution (in liters) = (volume of solution in milliliters) / 1000
= 23.45 mL / 1000

Finally, we can determine the molarity of the NaOH base:

Molarity of NaOH = (moles of KHP) / (volume of solution in liters)

Now, you can substitute the values into the equation to find the answer.