At 25 °C, only 0.0340 mol of the generic salt AB is soluble in 1.00 L of water.
What is the Ksp of the salt at 25 °C?
AB(s)↽−−⇀A+(aq)+B−(aq)
I get .0012 but that is wrong apparently. Help please!
To find the Ksp (solubility product constant) of the salt AB, you need to use the given information that at 25 °C, only 0.0340 mol of AB is soluble in 1.00 L of water.
The balanced equation for the dissociation of AB is:
AB(s) ⇌ A+(aq) + B-(aq)
The equilibrium expression for the solubility equilibrium of AB is:
Ksp = [A+][B-]
Since AB dissociates into one A+ ion and one B- ion, the concentration of A+ ions and B- ions will be the same at equilibrium.
Let's assume that the concentration of A+ and B- ions at equilibrium is x mol/L.
Then, you can express the Ksp in terms of x:
Ksp = [A+][B-] = x * x = x^2
Now, substitute the given values into the equation to solve for x:
0.0340 mol/L = x^2
Take the square root of both sides of the equation:
x = sqrt(0.0340 mol/L)
Calculate the square root:
x ≈ 0.184 mol/L
Finally, substitute the value of x back into the Ksp equation:
Ksp = [A+][B-] = (0.184 mol/L) * (0.184 mol/L) = 0.0339 mol^2/L^2
Round the answer to the appropriate number of significant figures, giving:
Ksp ≈ 0.034 mol^2/L^2
Therefore, the correct Ksp value for the salt AB at 25 °C is approximately 0.034 mol^2/L^2.
To determine the solubility product constant (Ksp) of a salt, you need to know the concentration of the dissociated ions in a saturated solution at a given temperature.
Given that only 0.0340 mol of the salt AB is soluble in 1.00 L of water at 25 °C, you can determine the concentration of the ions A+ and B- in the solution.
Since one molecule of the salt AB dissociates into one A+ ion and one B- ion, the molar concentration of both A+ and B- in the solution will be equal to 0.0340 M.
Now, to calculate the Ksp, you can use the formula:
Ksp = [A+][B-]
Since the concentration of both A+ and B- is 0.0340 M, substitute the values into the formula:
Ksp = (0.0340)(0.0340)
Calculating this, you get:
Ksp = 0.001156
Therefore, the Ksp of the salt AB at 25 °C is approximately 0.0012, which is the answer you obtained.
However, if it is considered incorrect, please double-check the question or consult your instructor, as there may be additional information or a specific method required to find the answer.