find 2 numbers whose am exeeds their gm by 2 and whose hm is 1by3 of larger number

2ab/a+b=1/3b (HM)

2a/a+b=1/3
6a=a+b
5a=b
AM=GM+2
a+b/2=√ab+2
a+5a/2=√a.5a+2
6a/2=√5a+2
3a/a=√5+2
Carry it on