I need help with:
What are the perimeter and area of a rectangle with a length of 20 in and a width of 15 in?
A. P=35 in., A=300 in. to the second power
B. P=70 in., A=300 in. to the second power
C. P=300 in., A=70 in. to the second power
D. P=35 in., A=200 in. to the second power
Please, someone, help me!!!
Perimeter = 2 times the length + 2 times the width
Area = length times width
I don't understand
Suppose my backyard measures 30 by 100 feet.
P = 2L + 2W
P = 2(100) + 2(30)\
P = 260 feet
A = LW
A = 30 * 100
A = 3,000 square feet
https://www.mathsisfun.com/geometry/rectangle.html
To find the perimeter of a rectangle, you need to add up the lengths of all its sides. In this case, the rectangle has a length of 20 inches and a width of 15 inches.
To calculate the perimeter, you need to add the lengths of all four sides. For a rectangle, the opposite sides are equal in length. So, you can determine the perimeter by adding twice the length and twice the width.
Perimeter = 2(length) + 2(width)
= 2(20) + 2(15)
= 40 + 30
= 70 inches.
Therefore, the perimeter of the rectangle is 70 inches.
To find the area of a rectangle, you need to multiply its length by its width.
Area = length × width
= 20 × 15
= 300 square inches.
Therefore, the area of the rectangle is 300 square inches.
Comparing these calculations with the given options, we can see that the correct answer is:
B. P=70 in., A=300 in².