Chemistry

For the reaction 2HI=H2+I2.one mole of HI is introduced into a vessel at constant temperature.calculate the no of moles of I2 when equilibrium is reached (Kc=0.0156)
Plz help me and give complete solution

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  1. 2HI>>H2 +I2
    letting x be the conc of (I2)
    The initial concentration of HI is 1mole/vol

    K=x^2/(1-(2x))

    .0156-.312x-x^2=0

    x=(.312+-sqrt(.312^2+.0624))/(-2)

    x= .0438 moles

    check my math, it is easy to make an error.

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    bobpursley
  2. I can't understand .312x how this value come i mean from where?

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  3. K=x^2/(1-(2x)) = 0.0156
    It comes from 0.0156 * 2

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