a 400 kg block of iron is heated from 295 k to 325 k. how much heat is absorbed by the iron? ( the specific heat is 450 j. /kg. k)
Well, heating up a block of iron, eh? Sounds like an iron-tense situation! But don't worry, I'm here to help with a little heat humor!
To calculate the amount of heat absorbed by the iron, we can use the formula:
Q = m * c * ΔT
Where Q is the heat absorbed, m is the mass, c is the specific heat, and ΔT is the change in temperature.
Now, let's crunch some numbers and iron out the details. We have a mass of 400 kg, a specific heat of 450 J/(kg·K), and a temperature change of 325 K - 295 K = 30 K.
Plugging these values into the formula, we get:
Q = 400 kg * 450 J/(kg·K) * 30 K
Now it's time for some multiplication magic! 400 times 450 equals...18,000. And 18,000 times 30 equals...540,000!
So, drumroll please...the amount of heat absorbed by the iron is 540,000 J!
Hope that puts a smile on your face, just like the heat put a smile on the iron block's face...if it had one!
To calculate the heat absorbed by the iron block, we can use the formula:
Q = mcΔT
Where:
Q = Heat absorbed (in joules)
m = Mass of the iron block (in kilograms)
c = Specific heat capacity of iron (in joules per kilogram per Kelvin)
ΔT = Change in temperature (in Kelvin)
Given:
Mass of the iron block (m) = 400 kg
Specific heat capacity of iron (c) = 450 J/(kg·K)
Change in temperature (ΔT) = 325 K - 295 K = 30 K
Substituting the given values into the formula, we get:
Q = (400 kg) x (450 J/(kg·K)) x (30 K)
Q = 5,400,000 J
Therefore, the iron block absorbs 5,400,000 joules of heat.
To calculate the amount of heat absorbed by the iron, you can use the formula:
Q = m * c * ΔT
Where:
Q represents the heat absorbed (in joules),
m is the mass of the iron block (in kilograms),
c is the specific heat capacity of iron (in joules per kilogram per kelvin),
and ΔT is the change in temperature (in kelvin).
Given:
mass of the iron block (m) = 400 kg
specific heat capacity of iron (c) = 450 J/kg·K
change in temperature (ΔT) = 325 K - 295 K = 30 K
Now we can plug in the values into the formula:
Q = 400 kg * 450 J/kg·K * 30 K
Q = 5,400,000 J
Therefore, the iron block absorbs 5,400,000 joules of heat.
heat=mass*specheat*changinTemp
= 400*450*(325-295) joules