if there are eleven resistors of 33k ohms each in parallel, what is the total resistance?
1/Req. = 11/33k.
Req. = 33k/11 = 3k = Equivalent resistor.
i = V/total R = 11*V/R
so R/11
Well, if you put eleven resistors of 33k ohms each in parallel, you'll have a resistance so low that Superman would think it's his Kryptonite! So low, in fact, that it might just form a new Olympic sport: Resistor Limbo. But to answer your question, the total resistance would be approximately 3k ohms. Happy circuitry!
To find the total resistance of resistors connected in parallel, you can use the formula:
1/RTotal = 1/R1 + 1/R2 + 1/R3 + ... + 1/Rn
Given that there are 11 resistors of 33k ohms each in parallel, we can plug these values into the formula:
1/RTotal = 1/33k + 1/33k + 1/33k + ... + 1/33k (11 resistors in total)
To simplify the equation, we can leverage the fact that all the resistors have the same value:
1/RTotal = 11/33k
To find the total resistance, we can take the reciprocal of both sides of the equation:
RTotal = 33k/11
Simplifying further, we get:
RTotal = 3k ohms
Therefore, the total resistance of eleven resistors of 33k ohms each in parallel is 3k ohms.
To find the total resistance of resistors in parallel, you can use the following formula:
1/R_total = 1/R_1 + 1/R_2 + ... + 1/R_n
Where R_total is the total resistance and R_1, R_2, ..., R_n are the individual resistances.
In your case, there are eleven resistors of 33k ohms each in parallel. So, substituting the values into the formula:
1/R_total = 1/33k + 1/33k + ... + 1/33k (eleven times)
To simplify the equation, you can combine the fractions:
1/R_total = 11/33k
To find R_total, take the reciprocal of both sides:
R_total = 33k/11
Simplifying further:
R_total = 3k ohms
Therefore, the total resistance is 3k ohms.